In repeated measurements in volumetric analysis, the end-points were observed as 11.15 mL, 11.17 mL, 11.11 mL and 11.17 mL.
In repeated measurements in volumetric analysis, the end-points were observed as 11.15 mL, 11.17 mL, 11.11 mL and 11.17 mL.
Calculate mean absolute deviation and relative deviation.
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Mean = \(\frac{11.15+11.17+11.11+11.17}{4}\)
= 11.15
| Measurement | End-point | Absolute deviation = |Observed value – Mean| |
| 1 | 11.15 mL | 0 |
| 2 | 11.17 mL | 0.02 mL |
| 3 | 11.11 mL | 0.04 mL |
| 4 | 11.17 mL | 0.02 mL |
Mean absolute deviation = \(\frac{0+0.02+0.04+0.02}{4}\)
= 0.02
∴ Mean absolute deviation = \(\pm0.02\,mL\)
Relative deviation = \(\frac{Mean\,absolute\,deviation}{Mean}\) x 100%
= \(\frac{0.02}{11.15}\) x 100%
= 0.2%
∴ i. Mean absolute deviation = ±0.02 mL
ii. Relative deviation = 0.2%
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