If R is the radius of the Earth and g is the acceleration due to gravity on the Earth’s surface, the mean density of the Earth is
(A) \(\frac{4g}{3\pi RG}\)
(B) \(\frac{4\pi RG}{3g}\)
(C) \(\frac{\pi Rg}{12g}\)
(D) \(\frac{3g}{4\pi RG}\)
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The value of acceleration due to gravity is maximum at
Correct answer is (C) the pole of the Earth.
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What is the variation in acceleration due to gravity with altitude?
Variation in acceleration due to gravity due to altitude is given by, gh = g\(\left(\frac{R}{R + h}\right)^2\) where, gh = acceleration due to gravity of an object placed at h altitude g = acceleration...
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The value of acceleration due to gravity increases as we move from equator to poles. For a given simple pendulum, a comstant time period can be achiev
Correct Answer - Increasing
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Discuss the variation of acceleration due to gravity at poles and equator due to latitude of the Earth.
1. Effective acceleration due to gravity at P is given as, g’ = g – Rω2cos2θ. 2. As the value of θ increases, cos θ decreases. Therefore g’ will increase as we...
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Find the altitude at which the acceleration due to gravity is 25% of that at the surface of the Earth.
Given: gh = 25% of g = \(\frac{25}{100}\times\,g=\frac{g}{4}\), R = 6400 km = 6.4 × 106 m To find: Height (h) Formula: gh = \(g(\frac{R}{R+h})^2\) Calculation: From formula, \(\frac{g}{4}=g(\frac{R}{R+h})^2\) (R + h)2 = 4R2 R + h = 2R ∴ h = 2R – R ∴ h...
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Derive the expression for the critical velocity of a satellite revolving close to the surface of the Earth in terms of acceleration due to gravity.
1. When the satellite is revolving close to the surface of the Earth, the height is very small as compared to the radius of the Earth. 2. Hence the height can...
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Acceleration due to gravity above the Earth’s surface at a height equal to the radius of the Earth is ______
Correct option is: (A) 2.5 m/s2
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Calculate angular velocity of Earth so that acceleration due to gravity at 60° latitude becomes zero.
Correct option is: (D) 2.5 × 10-3 rad/s
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If 1 kg body weights 1.2 N and 2 kg body weights 2.4 N on a planet. Then the acceleration due to gravity on that planet is
Correct option is D) 1.2 m/s2
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When we move away from the surface of the earth, the acceleration due to gravity value
Correct option is A) Decreases
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