Find the maximum and minimum values of `f(x)=sinx+1/2cos2x` in `[0, pi//2]` .
Find the maximum and minimum values of `f(x)=sinx+1/2cos2x` in `[0, pi//2]` .
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Correct Answer - max. value is `(3)/(4) " at " x = (pi)/(6)` and min. value is `(1)/(2) " at " x = (pi)/(2)`
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