Find both the maximum and the minimum value of `3x^4-8x^3+12 x^2-48 x+1` on the interval `[1, 4]` .

Find both the maximum and the minimum value of `3x^4-8x^3+12 x^2-48 x+1` on the interval `[1, 4]` .

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - max. value is 257 at `x = 4` and min. value is `-63` at x = 2

5 views Answered 2023-02-05 15:29

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