Find `(dy)/(dx)`, when: `y=x^(sinx)+(sinx)^(cosx)`
Find `(dy)/(dx)`, when:
`y=x^(sinx)+(sinx)^(cosx)`
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Correct Answer - `x^(sinx).{(sinx)/(x)+cosx.logx}+(sinx)^(cosx).{cosxcot x-sin x log(sinx)}`
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