In water molecule, the bond angle of `104.5^(@)` around oxygen is accounted due to
A. Repulsion between lone pair and bond pair
B. `sp^(3)` hybridization of O
C. Bonding of `H_(2)O`
D. Higher electronegativity of O

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1 Answers

The correct answer is (A). Repulsion between lone pair and bond pair.

This is as per VSEPR theory.

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