2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2 Compare the structure of the substrate propanol with that of the product sodium propoxide.
Consider the following reaction :
2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2
Compare the structure of the substrate propanol with that of the product sodium propoxide. Which part of the substrate, the carbon skeleton or the OH group has undergone a change during the reaction?
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In above reaction,
The -OH group of the substrate molecule has undergone a change.
The H-atom of hydroxyl group (-OH) is replaced by sodium forming the product.
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