A person is walking to the east at 2 km/hr and the rain drops appear to him dropping vertically downwards at `2sqrt(3)km//hr`. Find the actual velocity of rain.
Correct Answer - B
(2) Tangent to `y^(2)=4x` in terms of m is
`y=mx+(1)/(m)` (1)
Normal to `x^(2)=4by` in terms of m is
`y=mx+2b+(b)/(m^(2))` (2)
Equation (1) and (2) represent same...