For the given compound `CH_(3)-underset(overset(|)(OH))(CH)-CH=CH-CH_(3).` (i) Total number of stereoisomers. (ii) Number of opticallly active stereoi
For the given compound `CH_(3)-underset(overset(|)(OH))(CH)-CH=CH-CH_(3).`
(i) Total number of stereoisomers.
(ii) Number of opticallly active stereoisomers.
(iii) Total number of fractions on fractional distillation of all stereoisomers.
4 views
1 Answers
Correct Answer - (I) `CH_(3)-underset(overset(|)(OH))(C)H-CH=CH-CH_(3)`
Number of stereocentres = 2 so total number of stereoisomers = `2^(2)` = 4
(II) All 4 isomers are optically active. (III) Total enantiomeric pairs are 2, hence number of fraction will be 2.
4 views
Answered