In a box, there are 20 marbles. Each marble is marked with a distinct number from 1 to 20. Find the probability of drawing a marble from the box which is marked with a number that is a perfect square.
Correct Answer - D
According to the givn condition,
`""^(n)C_(3)((1)/(2))^(n)=""^(n)C_(4)((1)/(2))^(n),`
where n is the number of times die is thrown.
`therefore""^(n)C_(3)=""^(n)C_(4)impliesn=7`
Thus, the required probability is
`=""^(7)C_(1)((1)/(2))^(7)=(7)/(2^(7))=(7)/(128)`
Correct Answer - D
Let X denote the largest number on the 3 sticks drawn. Then, `P(Xle7)=(7//20)^(3)and P(Xle6)=(6//20)^(3).` Then, the required probability is
`P(X=7)=((7)/(20))^(3)-((6)/(20))^(3)`
Correct Answer - A::B::C
`(a,b,c)` Let the no. of blue marbles is `a` and no. of green marbles is `b` .
`:.(ab)/("^(a+b)C_(2))=(1)/(2)`
`implies(a+b)(a+b-1)=4ab`
`impliesb^(2)-(2a+1)b+a^(2)-a=0`
but `b in R implies D=(2a+1)^(2)-4(a^(2)-a)=8a+1`
`:....