Assuming 1 metric ton of coal gives heat of combustion equal to 8 kcal and a single fission of `.^(235)U` releases 200 MeV. Calculate the minimum consumption in kg of `.^(235)U` to be heat equivalent ot 100 ton of coal

4 views

1 Answers

Correct Answer - `[M = 4.077 xx 10^(-8) kg]`

4 views

Related Questions