`._(92)U^(238)` on absorbing a neutron goes over to `._(92)U^(239)`. This nucleus emits an electron to go over to neptunium which on further emitting

Question

`._(92)U^(238)` on absorbing a neutron goes over to `._(92)U^(239)`. This nucleus emits an electron to go over to neptunium which on further emitting

`._(92)U^(238)` on absorbing a neutron goes over to `._(92)U^(239)`. This nucleus emits an electron to go over to neptunium which on further emitting an electron goes over to plutonium. How would you represent the resulting plutonium ?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `_(94)Pu^(239)`

5 views Answered 2023-02-05 15:29