A battery of 24 cells each of emf 1.5 V and internal resistnace `2Omega` is to be connected in order to send the maximum current through a `12Omega` resistor. The correct arrangement of cells will be
A. 2 rows of 12 cells connected in parallel
B. 3rows of 8 cells connected in parallel
C. 4 rows of 6 cells connected in parallel
D. All of these

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 Let us connect cells in mixed grouping where n cells are connected in series in one row and m such rows are connected in parallel.

Let N = Nr = 24

Then for maximum current in external resistance.

\(r=\sqrt{\frac{NR}{r}}=\sqrt{\frac{24\times12}{2}}=12\)

\(m=\frac Nn=2.\)

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