An electric kettle has two windings. When one of the n is switched on the kettle begins to boil in `t_(1)` minutes and when the other is switched on it begins to boil in `t_(2)` minutes. In what time will the kettle begin to boil if both windings are switched on simultaneously in series and a parallel?

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Correct Answer - `t_(1)+t_(2),(t_(1)t_(2))/(t_(1)+t_(2))`

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