The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to a current loop wound around the magnetic equator of the eart

Question

The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to a current loop wound around the magnetic equator of the eart

The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to a current loop wound around the magnetic equator of the earth, then what should be the magnitude of the current? Take earth to be a sphere of radius `6400km`.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - ` 5 xx 10^(7) A`

4 views Answered 2023-02-05 15:29