A slab of copper of thckness t is thrust into a parallel plate capacitor of area A and plate separation d. What is the capacitance before and after th

A slab of copper of thckness t is thrust into a parallel plate capacitor of area A and plate separation d. What is the capacitance before and after the slab is introduced?
[Hint:There is no electric field inside a copper slab, or we may say that metals are isulators of `epsilon_(r)=infty]`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - `(epsilon_(0)A)/(d),(epsilon_(0)A)/(d-1)`

5 views Answered 2023-02-05 15:29

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