An infintie nonconducting sheet a surface density of change `sigma` Around the foot og the perpendicular from a point P a circle of radius r is drawn

An infintie nonconducting sheet a surface density of change `sigma` Around the foot og the perpendicular from a point P a circle of radius r is drawn .Find the valume of r at which the field at P product by changes inside this circle is half of the total strength of the feld due to the entire sheet . The distance of the point P is a from the plane.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - `r=sqrt()3a`

5 views Answered 2023-02-05 15:29

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