Determine the conductivity of pure germanium at `27^(@)C`. The concentration of the carriers at this temperature is `2.2 xx 10^(19)m^(-3)`. The mobili

Question

Determine the conductivity of pure germanium at `27^(@)C`. The concentration of the carriers at this temperature is `2.2 xx 10^(19)m^(-3)`. The mobili

Determine the conductivity of pure germanium at `27^(@)C`. The concentration of the carriers at this temperature is `2.2 xx 10^(19)m^(-3)`. The mobility of electrons = 0.36 and that of holes = 0.17

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `1.87 Omega^(-1)m^(-1)`

4 views Answered 2023-02-05 15:29