Calculate the moment of a magnet, which when placed at right angles to the horizontal magnetic field of the earth of intensity `30 Am^(-1)` experiences a couple of `3 xx 10^(-4)` newton metre.
[Hint: `B_(0) = mu_(0)H_(0) = 4pi xx 10^(-7) xx 30 `tesla and `tau = mB_(0) sin theta`]

5 views

1 Answers

Correct Answer - `7.958 Am^(2)`

5 views

Related Questions