An electron is moving with a velocity of `2 xx 10^(6)ms^(-1)` in the vicinity of a 0.1 m long bar magnet of pole strength 50 Am in a direction perpendicular to the axis of the magnet at a distance of 0.15 m from the nearer pole. What is the force on the electron ? Charge of electron `= 1.6 xx 10^(-19)C`
[Hint: Calculate B-vector of the field and apply `F = q_(0)vB sin theta`]

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Correct Answer - `4.6 xx 10^(-17)N`

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