A current of 0.5 amp is passed through excess of molten mixture of `Al_(2)O_(3)` and `Na_(3)AlF_(6)` for 9.65 hours. The mass of Al (in mg) deposited

Question

A current of 0.5 amp is passed through excess of molten mixture of `Al_(2)O_(3)` and `Na_(3)AlF_(6)` for 9.65 hours. The mass of Al (in mg) deposited

A current of 0.5 amp is passed through excess of molten mixture of `Al_(2)O_(3)` and `Na_(3)AlF_(6)` for 9.65 hours. The mass of Al (in mg) deposited at the cathode, with (100/12)% current efficiency is (Al = 27).

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 1350

5 views Answered 2023-02-05 15:29