A coin is tossed 8 times. The probability of getting exactly 5 heads is -

(A) \(\left(\frac{1}{2}\right)^5\)

(B) \(\left(\frac{1}{2}\right)^8\)

(C) \(^8C_5 \left(\frac{1}{2}\right)^8\)

(D) \(^8C_5 \left(\frac{1}{2}\right)^5\)

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Correct answer is (C) \(^8C_5 \left(\frac{1}{2}\right)^8\)

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