The remainder when `27^(10)+7^(51)` is divided by `10`
The remainder when `27^(10)+7^(51)` is divided by `10`
A. `4`
B. `6`
C. `9`
D. `2`
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Correct Answer - D
`(d)` `(27)^(10)+7^(51)=(30-3)^(10)+(10-3)^(51)`
`=3^(10)-3^(51)+10lambda`
`=(10-1)^(5)-3(10-1)^(25)+10lambda`
`=-1+3+10lambda_(1)`
`=2+10lambda_(1)`
`:.` Remainder is `2`
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