If `z+1/z=2cos6^@` , then `z^1000+1/[z^1000]` +1 is equal to
If `z+1/z=2cos6^@` , then `z^1000+1/[z^1000]` +1 is equal to
A. `0`
B. `1`
C. `-1`
D. `2`
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Correct Answer - A
`(a)` `z+(1)/(z)=2cos6^(@)`
`:.z=cos6^(@)+-isin6^(@)`
`impliesz^(1000)+(1)/(z^(1000))+1=2cos6000^(@)+1=2xx(-(1)/(2))+1=0`
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