The value of `sum_(n=0)^(100)i^(n!)` equals (where `i=sqrt(-1))`
The value of `sum_(n=0)^(100)i^(n!)` equals (where `i=sqrt(-1))`
A. `-1`
B. `i`
C. `2i+95`
D. `97+i`
5 views
1 Answers
Correct Answer - C
`(c )` `S=sum_(n=0)^(100)(i)^(n!)`
`=(i)^(0!)+(i)^(1!)+(i)^(2!)+…..`
`=i+i-1+i^(6)+i^(24)+(i)^(5!)+(i)^(6!)+..+(i)^(100!)`
`=95+2i`
5 views
Answered