`(1+tanalphatanbeta)^2+(tanalpha-tanbeta)^2=`
A. `tan^2alphatan^2beta`
B. `sec^2alphasec^2beta`
C. `tan^2alphacot^2beta`
D. `sec^2alphacos^2beta`

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1 Answers

Correct Answer - B
`(1+tanalphatanbeta)^2+(tanalpha-tanbeta)^2`
`=1+2tanalphatanbeta+tan^2alphatan^2beta+tan^2alpha+tan^2beta-2tanlphatanbeta`
`=1tan^2alphatan^2beta+tan^2alpha+tan^2beta`
`+(1+tan^2alpha)(1+tan^2beta)`
`=sec^2alphasec^2beta`

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