In `Delta ABC, (sin A (a - b cos C))/(sin C (c -b cos A))=`

In `Delta ABC, (sin A (a - b cos C))/(sin C (c -b cos A))=`
A. `-2`
B. `-1`
C. 0
D. 1

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - D
`(sinA (a -b cos C))/(sinC (c -b cos A))`
`= (sin A (b cos C + c cos B - cos C))/(sin C (a cos B + b cos A - b cos A))`
`= (sin A (c cos B))/(sin C (a cos B))`
`=1 " " ("as " c sin A = a sin C)`

6 views Answered 2023-02-05 15:29

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