`"If " int(5tanx)/(tanx-2)dx=x+a " In"(sinx-2cosx)+k " then " a= `
`"If " int(5tanx)/(tanx-2)dx=x+a " In"(sinx-2cosx)+k " then " a= `
A. -1
B. -2
C. 1
D. 2
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Correct Answer - D
` int(5tanx)/(tanx-2)dx=int(5sinx)/(sinx-2cosx)dx`
`=int((sinx-2cosx)+2(cosx+2sinx))/((sinx-2cosx))dx`
`=int dx+2int(cosx+2sinx)/(sinx-2cosx)dx`
`=x+2 " In"|(sinx-2cosx)|+k`
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