Define resolving power of an astronomical refracting telescope and write expression for it in normal adjustment.Assume that light of wave length 6000Å

Question

Define resolving power of an astronomical refracting telescope and write expression for it in normal adjustment.Assume that light of wave length 6000Å

Define resolving power of an astronomical refracting telescope and write expression for it in normal adjustment.Assume that light of wave length 6000Å is coming from a star, what is the limit of resolution of a telescope whose objective has a diameter of 2.54m?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Resolving power (R.P) of astronomical telescope is its ability of form separate images of two neighboring
astronomical objects like stars etc.
`"R.P" = (1)/(d theta) = (D)/(1.22lambda)` where D is diameter of objective lens and `lambda` is wave length of light used.
`D = 100"inch" = 2.54 xx 100"cm" = 254"cm"`
= 2.54m
`lambda = 6000 Å`
Limit of resolution `d theta = (1.22 lambda)/(D)`
`= (1.22 xx 6000 xx 10^(-10)m)/(254 xx 10 ^(-2)m)`
` = 2.9 xx 10^(-10)`