Vertices of a parallelogram taken in order are A, ( 2,-1,4) , B (1,0,-1) , C ( 1,2,3) and D.
The distance between the parallel lines AB and CD is
A. 14, 4,2
B. 2,4,14
C. 4,2,14
D. 2,14,4

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1 Answers

Correct Answer - d
vector normal to the plane
`vec(AD)xxvec(AB)+(7hati+2hatj-hatk)`
Projection on xy=2
Projection on yx= 14
projection on zx = 4

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