I the vectors `veca,veca=xhati+yhatj+zhatka and vecb=hatj` are such that `veca,vecc and vecb` form a righat handed system then `vecc` is (A) `zveci-xveck` (B) `vec0` (C) `yhatj` (D) `-zhati+xhatk`

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Since `veca ,vecc and vecb` form a right - handed system,
`vecc = vecb xx veca`
`= hatj xx (xhati + y hatj + z hatk) `
= - x hatk + zhati = z hati - x hatk`

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