If `veca,vecb,vecc` are mutually perpendicular vector and `veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecal

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If `veca,vecb,vecc` are mutually perpendicular vector and `veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecal

If `veca,vecb,vecc` are mutually perpendicular vector and `veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecalpha+vecbeta+vecgamma=` (A) `|veca|^2` (B) `-|veca|^2` (C) 0 (D) none of these

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Taking dot poduct with `veca ,vecb and vecc` , respectively we get
`|veca|^(2)=beta.[vecavecbvecc]=beta`
`0=gamma.[veca vecbvecc]=gamma`
` and 0=alpha.[veca vecbvecc]=alpha`
`alpha+beta+gamma=|veca|^(2)`

5 views Answered 2023-02-05 15:29