Consider the three solvents of identical molar masses. Match their boiling point with their `K_(b)` values
`{:(ul(bar("Solvents" " ""Boiling point" " "K_(b) "values" " "))),(ul(X " " 100^(@)C " " 0.92 " ")),(ul(Y " " 27^(@)C " "0.63" ")),(ul(Z " " 283^(@)C " "0.53 " ")):}`

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Correct Answer - `0.23^(@)C`

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