A father has 3 children with at least one boy. The probability that he has 2 boys and 1 girl is `1//4` b. `1//3` c. `2//3` d. none of these

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A father has 3 children with at least one boy. The probability that he has 2 boys and 1 girl is `1//4` b. `1//3` c. `2//3` d. none of these

A father has 3 children with at least one boy. The probability that he has 2 boys and 1 girl is `1//4` b. `1//3` c. `2//3` d. none of these
A. `1//4`
B. `1//3`
C. `2//3`
D. None of these

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Consider the following events:
A: Father has at least one boy
B: Father has 2 boys and one girl
Then,
A= one boy and 2 girls, 2 boys and one girl, 3 boys and no girl `AnnB=2` boys and one girl
Now, the required probability is
`=P(A//B)=(P(AnnB))/(P(A))=1/3`

4 views Answered 2023-02-05 15:29