Three coins are tossed. If one of them shows tail, then find the probability that all three coins show tail.

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Correct Answer - `1//7`
Let E be the event which all three coins show tail and F be the event in which a coin shown tail. Therefor, `F={HHT}.` Hence, the required probability is
`thereforeP(E//F)=(P(EnnF))/(P(E))=(1)/(7)`

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