If the number of terms in the expansion of `(x+y+z)^n` are 36, then find the value of `ndot`
If the number of terms in the expansion of `(x+y+z)^n` are 36, then find the value of `ndot`
6 views
1 Answers
Correct Answer - `n = 7`
Number of terms in the expansion of `(x+y+z)^(n)` is
`(n+1)(n+2)=36`
or ` (n+1)(n+2) = 72`
or `n = 7`
6 views
Answered