A heat engine works between a source and a sink maintaned at constant temperatures `T_(1)` and `T_(2)`. For the efficiency to be greatest
A. `T_(1)`m and `T_(2)`. Should be high
B. `T_(1)` and `T_(2)` should be low
C. `T_(1)` should be low and `T_(2)` should be high
D. `T_(1)` should be high and `T_(2)` should be low

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1 Answers

`eta=1-(T_(2))/(T_(1))`

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