Two flask X and Y have volume 1 L and 2 L respectively and each of them contain 1mole of same ideal gas. The temperature of the flask are so adjusted
Two flask X and Y have volume 1 L and 2 L respectively and each of them contain 1mole of same ideal gas. The temperature of the flask are so adjusted that average speed of molecules in X is twice as those in Y. The pressure in flask X would be:
A. same as that in Y
B. half of that in Y
C. `(1)/(8)th` of that in Y
D. 8 times of that in Y
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`PV=(1)/(3)MnU_("rms")^(2)`
Since `(U_(avg))_(x)=2(U_(avg))_(y)`
`P_(x)(I)=4xxP_(y)xx2`
`P_(x)=8P_(y)`
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