What is oxidation? Which one of the following pairs of species is in its oxidized state?

Question

What is oxidation? Which one of the following pairs of species is in its oxidized state?

What is oxidation? Which one of the following pairs of species is in its oxidized state?

a. Mg / Mg²⁺

b. Cu / Cu²⁺

c. O₂ / O^2-

d. Cl₂/ Cl^-

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

Related Questions

In which pairs is are the stronger bond found in the first species ?

2 Answers 4 Views

In which of the following oxoanions the oxidation state of central atom is not same as that of its group number in periodic table ?

2 Answers 4 Views

`H_3PO_3+HNO_3+(NH_4)_2MoO_4to` Oxidation number of Mo in product is x. `Cr_2O_7^(2-)+H^(+)+NaCl to` Oxidation state of Cr in product is y. `SCN^(-)+M

2 Answers 4 Views

If `X^(a)` species emit firstly a positron then two `alpha` and `beta` last one `alpha` is also emitted and finally convert in `Y^(c )` species so cor

2 Answers 4 Views

For which of these oxidation/reduction pairs will the reduction potential vary with pH? I `AmO_(2)^(2+)//AmO_(2)^(+)` II. `AmO_(2)^(2+)//Am^(4+)` III

2 Answers 7 Views

Which one of the following pairs correctly matches a hormone with a disease resulting from its deficiency ?

2 Answers 4 Views

Final the total number of species having two unparired electron from the following species, `Fe^(2+),Cr,Cr^(3+),Ti^(2+),V^(3+)`

2 Answers 5 Views

(i) What is the interaction between two species called ? (ii) Name the association in which one species producers poisonous substance or a change in e

2 Answers 8 Views

(a) Account for the following : (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +

2 Answers 7 Views

For each of the following pairs, indicate which of the two species is of large size : a. Fe^(2+) or Fe^(3+) b. Mg^(2+) or Ca^(2+)

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

a. Mg/Mg²⁺

Here,

Mg loses two electrons to form Mg²⁺ ion.

Mg_(s) ⟶ Mg²⁺_(aq) + 2e^-

Hence,

Mg/Mg²⁺ is an oxidized state.

b. Cu/Cu²⁺

Here,

Cu loses two electrons to form Cu²⁺ion.

Cu_(s) ⟶ Cu²⁺_(aq) + 2e^-

c. O₂/O^2-

Here,

Each O^2- gains two electrons to form O^2-ion.

Hence,

O₂/O^2-

d. Cl₂/Cl^- is in a reduced state.

Here,

Each Cl gains one electron to form Cl^- ion.

Cl_2(g) + 2e^- ⟶2 − Cl^-_(aq)

Hence,

Cl₂/Cl^- is in a reduced state.