If screening does not split the subshell(l) of a given shell(n), how many elements would occur in 5th period.

If screening does not split the subshell(l) of a given shell(n), how many elements would occur in 5th period.
A. 50
B. 32
C. 18
D. 64

Monjur Alahi

14 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

then no of electrons in 5th shell=no. of electron in 5th pd=2xxn^(2)=2xx5^(2)=50`

14 views Answered 2023-02-05 15:29

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