If `)-4,0)` and `(1,-1)` are two vertices of a triangle of area `4s qdotu n i t s ,` then its third vertex lies on `y=x` (b) `5x+y+12=0` `x+5y-4=0` (d

Question

If `)-4,0)` and `(1,-1)` are two vertices of a triangle of area `4s qdotu n i t s ,` then its third vertex lies on `y=x` (b) `5x+y+12=0` `x+5y-4=0` (d

If `)-4,0)` and `(1,-1)` are two vertices of a triangle of area `4s qdotu n i t s ,` then its third vertex lies on `y=x` (b) `5x+y+12=0` `x+5y-4=0` (d) `x+5y+12=0`
A. `y=x`
B. `5x+y+12=0`
C. `x+5y-4=0`
D. `x+5y+12=0`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C::D
Let the third vertex be (x,y) then. ,
`(1)/(2)|{:(x,,y,,1),(-4,,0,,1),(1,,-1,,1):}|=+-4`
`rArrx+5y+4=+-8`
`rArrx+5y+12=0 or x+5y-4=0`
Hence, the third vertex lies on `x+5y+12=0 or x+5y-4=0`.

4 views Answered 2023-02-05 15:29