For hyperbola `x^2/a^2-y^2/b^2=1` , let n be the number of points on the plane through which perpendicular tangents are drawn.

Question

For hyperbola `x^2/a^2-y^2/b^2=1` , let n be the number of points on the plane through which perpendicular tangents are drawn.

For hyperbola `x^2/a^2-y^2/b^2=1` , let n be the number of points on the plane through which perpendicular tangents are drawn.
A. If n = 1, then `e=sqrt2`
B. If n gt 1, then `0 lt e lt sqrt2.`
C. If n = 0, then `e gt sqrt2`.
D. none of these

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A::B::C
The locus of the point of intersection of perpendicular tangents is director circle `x^(2)+y^(2)=a^(2)-b^(2)`. Now,
`e^(2)=1+(b^(2))/(a^(2))`
If `a^(2) gt b^(2)`, then there are infinite (or more than 1) points on the circle, i.e., `e^(2)lt2 or e ltsqrt2`. ltBrgt If `a^(2) lt b^(2)`, there does not exist any point on the plane, i.e.,
`e^(2) gt2 or e gtsqrt2`.
If `a^(2)=b^(2)`, there is exactly one point (center of the hyperbola),
i.e., `e=sqrt2`.