A hyperbola passes through (2,3) and has asymptotes `3x-4y+5=0` and `12 x+5y-40=0` . Then, the equation of its transverse axis is `77 x-21 y-265=0` `21 x-77 y+265=0` `21 x-77 y-265=0` `21 x+77 y-265=0`
A. `77x-21y-265=0`
B. `21x-77y+265=0`
C. `21x-77y-265=0`
D. `21x+77y-265=0`

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1 Answers

Correct Answer - B
Transverse axis is the equation of the angle bisector containing point (2, 3) which is given by
`(3x-4y+5)/(5)=(12x+5y-40)/(13)`
`"or "21x+77y=265`

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