Enthalpy of formation of HX(g) from `H_(2)(g)` and `X_(2)(g)` is - 516.52 KJ/mole. If the electronegativity of X greater than the electronegativity of
Enthalpy of formation of HX(g) from `H_(2)(g)` and `X_(2)(g)` is - 516.52 KJ/mole. If the electronegativity of X greater than the electronegativity of H is 2, what is the electronegativity of X?
We use given expression `-DeltaH_(1)=129.13 (Deltax)^(2)`, where `Deltax` is electronegativity difference.
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Correct Answer - 1
From stevenson formula
`d_(A-B)=r_(A)+r_(B)-0.09Deltax" "(ifX_(C)neX_(Cl))`
Given `d_(C-Cl)=1.76 Å, r_(C)=0.77Å, r_(Cl)=? `
`1.76 = 0.77 + r_(Cl)-0.09 xx|(2.5 - 3.0)|`
`r_(Cl)=1.03 Å`
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