Given three straight lines `2x+11 y-5=0,24 x+7y-20=0,` and `4x-3y-2=0` . Then, they form a triangle one line bisects the angle between the other two t

Question

Given three straight lines `2x+11 y-5=0,24 x+7y-20=0,` and `4x-3y-2=0` . Then, they form a triangle one line bisects the angle between the other two t

Given three straight lines `2x+11 y-5=0,24 x+7y-20=0,` and `4x-3y-2=0` . Then, they form a triangle one line bisects the angle between the other two two of them are parallel
A. they from a triangle
B. they are concurrent
C. one line bisects the angle between the other two
D. two of them are parallel

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
For the two lines 24x+7y-20=0 and 4x-3y-2=0, the angle bisectors are given by
`(24x+7y-20)/(25) =+-(4x-3y-2)/(5)`
Taking positive sign, we get
2x+11y-5=0

4 views Answered 2023-02-05 15:29