The total number of correct order of ionisation energy is :
`(Ne gt Ne^(+)),(O^(-) lt O),(N^(+) gtN), (Fe lt Fe^(2+)),(O^(-) gt O^(-2)), (F gt F^(-)),(Na gt Na^(+)), (Mg lt Mg^(2+)), (Na^(+) lt Mg^(2+)),(S^(-2) lt Cl^(-))`

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1 Answers

Correct Answer - 4
`10=(n(n-1))/(2)`
`n=5`
`4^(th)` excited state

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