`A B C` is a variable triangle such that `A` is (1, 2), and `Ba n dC` on the line `y=x+lambda(lambda` is a variable). Then the locus of the orthocentr

`A B C` is a variable triangle such that `A` is (1, 2), and `Ba n dC` on the line `y=x+lambda(lambda` is a variable). Then the locus of the orthocentre of `"Delta"A B C` is `x+y=0` (b) `x-y=0` `x^2+y^2=4` (d) `x+y=3`
A. x+y=0
B. x-y=0
C. `x^(2) + y^(2)=4`
D. x+y=3

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - D
As the altitude from A is fixed and the orthocenter lies on the altitude, x+y=3 is the required locus.

4 views Answered 2023-02-05 15:29

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