The equations of the sided of a triangle are `x+y-5=0,x-y+1=0,` and `x+y-sqrt(2)=0` is `(-oo,-4/3)uu(4/3,+oo)` `(-4/3,4/3)` (c) `(-3/4,4/3)` none of t

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The equations of the sided of a triangle are `x+y-5=0,x-y+1=0,` and `x+y-sqrt(2)=0` is `(-oo,-4/3)uu(4/3,+oo)` `(-4/3,4/3)` (c) `(-3/4,4/3)` none of t

The equations of the sided of a triangle are `x+y-5=0,x-y+1=0,` and `x+y-sqrt(2)=0` is `(-oo,-4/3)uu(4/3,+oo)` `(-4/3,4/3)` (c) `(-3/4,4/3)` none of these
A. `(-oo, -4//3) uu (4//3, +oo)`
B. (-4/3, 4/3)
C. (-3/4,4/3)
D. none of these

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
The distance between (2/m, 2) and (6/m, 6) is less than 5 Hence,
`((2)/(m) - (6)/(m))^(2) + (2-6)^(2) lt 25`
`"or " (16)/(m^(2)) lt 9`
`"or " m^(2) gt (16)/(9)`
`i.e., m gt (4)/(3) "or " m lt (-4)/(3)`

5 views Answered 2023-02-05 15:29