Value of all four quantum number for last `e^(-)` of elecment x in their ground state is n = 4, l = 1, m = 1 and `s=-1//2` and spin multiplicity of element x in their ground state is 4.
Find number of unpaired `e^(-1)` in element x is :
A. 2
B. 4
C. 3
D. 5

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1 Answers

Correct Answer - C
Total number of nodes = n - 1 = 4 - 1 = 3

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