A particle is projected from the ground at an angle of `60^(@)` with horizontal at speed `u = 20 m//s.` The radius of curvature of the path of the par

Question

A particle is projected from the ground at an angle of `60^(@)` with horizontal at speed `u = 20 m//s.` The radius of curvature of the path of the par

A particle is projected from the ground at an angle of `60^(@)` with horizontal at speed `u = 20 m//s.` The radius of curvature of the path of the particle, when its velocity. makes an angle of `30^(@)` with horizontal is :
`(g=10 m//s^(2)`
A. 10.6 m
B. 12.8 m
C. 15.4 m
D. 24.2 m

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`bar(V)_(B//P)=(3hat(i)+hat(j))-(7hat(i)-2hat(j))`
`vec(f)_(k)=-hatv_(B//P)=(4)/(5)hat(i)-(3)/(5)hat(j)`
friction will be opposite to relative velocity.

5 views Answered 2023-02-05 15:29